2 cars left points A and B at the same time, the distance between points is 20 km. Speed = 50 km / h

| May 19, 2021 | education

2 cars left points A and B at the same time, the distance between points is 20 km. Speed = 50 km / h, speed = 60 km / h. Determine the position of the car relative to point A 0.5 hour after the start of movement and calculate between the car during this time, as well as the distance traveled by the car.

V1 = 50 km / h.
V2 = 60 km / h.
S = 20 km.
t = 0.5 h.
S1a -?
S2а -?
S1 -?
S2 -?
S12 -?
The distance traveled by the car with uniform rectilinear movement is determined by the formula: S = V * t.
S1 = V1 * t.
S2 = V2 * t.
S1 = 50 km / h * 0.5 h = 25 km.
S2 = 60 km / h * 0.5 h = 30 km.
The first car will be located from point A at a distance S1a = S1.
S1а = 25 km.
The second car from point A will be at a distance S2а = S + S2.
S2а = 20 km + 30 km = 50 km.
The distance between cars S12 is determined by the formula: S12 = S + S2 – S1.
S12 = 20 km + 30 km – 25 km = 25 km.
Answer: S1 = 25 km, S2 = 30 km, S1а = 25 km, S2а = 50 km, S12 = 25 km.



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