2 l of solution contains 0.08 g of Ca (OH) 2. Find pH, pOH?

Let’s find the molar concentration of hydroxide ions. Since Ca (OH) 2 is a strong base and dissociates completely in an aqueous solution: [OH-] = 2 * c (Ca (OH) 2) = 2 * m (Ca (OH) 2) / М (Ca (OH) 2) / V (solution) = 2 * 0.08 / 75/2 = 1.06 * 10-3 mol / l

pOH = -lg (1.06 * 10-3) = 1.49

pH = 14 – 1.64 = 12.51



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