2 motorcyclists left A and B met at a distance of 9 km from And then, having reached B and A, turned around and drove on

| February 4, 2021 | education

2 motorcyclists left A and B met at a distance of 9 km from And then, having reached B and A, turned around and drove on. Met at a distance of 6 km from B. find: distance from A to B and the ratio of speeds

The time spent by the first motorcyclist before meeting the second from point A is t = 9 / v1, v1 is the speed of the first motorcyclist. During the same time, the second motorcyclist traveled the BO distance with a speed v2, i.e. t = BO / v2.
Let’s equate both sides of the equations:
9 / v1 = BO / v2, v1 / v2 = 9 / BO.
Let’s find the distance BO.
Returning from point B, the first motorcyclist drove 6 km at the same speed as from point A. But 3 km less, 9 – 6 = 3 km. This means that the distance OB is 3 km. And the distance from point A to B is 9 + 3 = 12 km.
Motorcycle speed ratio:
v1 / v2 = 9 / BO = 9/3 = 3.



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