2 point charges are at a distance r from each other, if the distance between them decreases by 50 cm
| September 11, 2021 | education
2 point charges are at a distance r from each other, if the distance between them decreases by 50 cm, the force of interaction will double. Find the distance between charges.
These tasks: Δr (change in the distance between the indicated charges) = 50 cm = 0.5 m; n – increase in the force of interaction (n = 2).
To find the distance between the indicated charges, we will use the ratio: n = Fк2 / Fк1 = (k * q1 * q2 / (r – Δr) ^ 2) / (k * q1 * q2 / r ^ 2) = r ^ 2 / (r – Δr) ^ 2 = 2.
Substitute the known values:
r ^ 2 = 2 * (r – 0.5) ^ 2.
r ^ 2/2 = (r – 0.5) ^ 2.
r * √0.5 = r – 0.5.
r – r * √0.5 = 0.5.
0.293r = 0.5 and r = 0.5 / 0.293 = 1.71 m.
Answer: The distance between the indicated charges is 1.71 m.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
