20 g was passed through a solution containing 10 g of potassium hydroxide.

20 g was passed through a solution containing 10 g of potassium hydroxide. hydrogen bromide. What salt was formed during this? Determine the mass and quantity.

Given:
m (KOH) = 10 g
m (HBr) = 20 g

To find:
m (salt) -?
n (salt) -?

Decision:
1) KOH + HBr => KBr + H2O;
2) M (KOH) = Mr (KOH) = Ar (K) * N (K) + Ar (O) * N (O) + Ar (H) * N (H) = 39 * 1 + 16 * 1 + 1 * 1 = 56 g / mol;
M (KBr) = Mr (KBr) = Ar (K) * N (K) + Ar (Br) * N (Br) = 39 * 1 + 80 * 1 = 119 g / mol;
3) n (KOH) = m (KOH) / M (KOH) = 10/56 = 0.18 mol;
4) n (HBr) = m (HBr) / M (HBr) = 20/81 = 0.25 mol;
5) n (KBr) = n (KOH) = 0.18 mol;
6) m (KBr) = n (KBr) * M (KBr) = 0.18 * 119 = 21.42 g.

Answer: The mass of KBr is 21.42 g; the amount of substance is 0.18 mol.