20 grams with a 10% solution of HNO3 reacted with Na2O. How many moles of salt did you get?

The equation for the reaction of sodium oxide with nitric acid:

Na2O + 2HNO3 = 2NaNO3 + H2O

Let’s find the mass of HNO3:

m (HNO3) = mr.-pa (HNO3) * w (HNO3) / 100 = 20 * 10/100 = 2 (g).

Let’s find the amount of the substance HNO3:

v (HNO3) = m (HNO3) / M (HNO3) = 2/63 = 0.03 (mol).

According to the reaction equation, 2 mol of NaNO3 is formed per 2 mol of HNO3, therefore:

v (NaNO3) = v (HNO3) = 0.03 (mol).

Answer: 0.03 mol.