200 g of boiling water was poured into a porcelain cup weighing 100 g at a temperature of 20 degrees.

200 g of boiling water was poured into a porcelain cup weighing 100 g at a temperature of 20 degrees. The final temperature was found to be 93 degrees. Determine the specific heat of porcelain.

Initial data: m1 (weight of a porcelain cup) = 100 g = 0.1 kg; t0 (initial cup temperature); m2 (mass of boiling water) = 200 g = 0.2 kg; t2 (final temperature) = 93 ºС.

Constants: t1 (boiling point of water) = 100 ºС; C (specific heat capacity of water) = 4200 J / (kg * K).

Thermal equilibrium:

Q1 (heating a porcelain cup) = Q2 (cooling boiling water) = C1 * m1 * (t2 – t0) = C2 * m2 * (t1 – t2).

C1 = C2 * m2 * (t1 – t2) / (m1 * (t2 – t0)) = 4200 * 0.2 * (100 – 93) / (0.1 * (93 – 20)) ≈ 805 J / ( kg * K).