200 g of sulfuric acid solution was added to the barium nitrate solution to give 9.32 g of salt.

200 g of sulfuric acid solution was added to the barium nitrate solution to give 9.32 g of salt. Calculate the acid fraction in the effluent solution.

Barium nitrate reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which turns into an insoluble precipitate. The reaction is described by the following chemical reaction equation.

Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3;

Barium nitrate reacts with sulfuric acid in equal molar amounts. In this case, the same amount of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; N BaSO4 = 9.32 / 233 = 0.04 mol;

The same amount of sulfuric acid will be used.

Let’s find its weight.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.04 x 98 = 3.92 grams;

The sulfuric acid concentration will be 3.92 / 200 = 0.0196 = 1.96%;