200 g of sulfuric acid solution was added to the barium nitrate solution to obtain 93.2 g of precipitate.

200 g of sulfuric acid solution was added to the barium nitrate solution to obtain 93.2 g of precipitate. What is the proportion of acid (in percent) in the original solution?

Barium nitrate reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which precipitates. The reaction is described by the following chemical reaction equation.

Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3;

Barium nitrate reacts with sulfuric acid in equal molar amounts. This produces the same amount of insoluble salt.

Find the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; N BaSO4 = 93.2 / 233 = 0.4 mol;

The same amount of sulfuric acid will be used.

Let’s calculate its weight.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.4 x 98 = 39.2 grams;

The sulfuric acid concentration will be 39.2 / 200 = 0.196 = 19.6%;