200 grams of water, the temperature of which was 15 degrees Celsius, was heated to 20 degrees.
March 17, 2021 | education
| 200 grams of water, the temperature of which was 15 degrees Celsius, was heated to 20 degrees. How much heat the water received.
Given: m = 0.2 kg, t1 = 15 oC, t2 = 20 oC. Find Q.
The amount of heat required for heating is determined by the formula Q = C * m * (t2 – t1), where C is the heat capacity of water, J / (kg * oC); m is the mass of water, kg; t1 – initial water temperature, oC; t2 – final water temperature, oC. From the reference book we find C = 4180 J / (kg * oC).
We substitute the data into the formula, consider: Q = C * m * (t2 – t1) = 4180 * 0.2 * (20 – 15) = 4180 J.
Answer: Q = 4180 J.
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