200 grams of water, the temperature of which was 15 degrees Celsius, was heated to 20 degrees.

200 grams of water, the temperature of which was 15 degrees Celsius, was heated to 20 degrees. How much heat the water received.

Given: m = 0.2 kg, t1 = 15 oC, t2 = 20 oC. Find Q.

The amount of heat required for heating is determined by the formula Q = C * m * (t2 – t1), where C is the heat capacity of water, J / (kg * oC); m is the mass of water, kg; t1 – initial water temperature, oC; t2 – final water temperature, oC. From the reference book we find C = 4180 J / (kg * oC).

We substitute the data into the formula, consider: Q = C * m * (t2 – t1) = 4180 * 0.2 * (20 – 15) = 4180 J.

Answer: Q = 4180 J.



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