200 tons of water is thrown down from the waterfall with a height of 18 seconds in 5 minutes

200 tons of water is thrown down from the waterfall with a height of 18 seconds in 5 minutes. how much power does it develop?

Waterfall power:

P = A / t, where A is the work done by water, t is the time (t = 5 min = 5 * 60 s = 300 s).

Water work:

A = F * S, where F is the applied force, F = Ft = m * g (m is the mass of water (m = 200 t = 200 * 10 ^ 3 kg)), g is the acceleration of gravity (we take g = 10 m / s2)); S – water movement, waterfall height (S = h = 18 m).

Let’s calculate the developed power:

P = A / t = m * g * h / t = 200 * 10 ^ 3 * 10 * 18/300 = 120,000 W = 120 kW.

Answer. The power is developing equal to 120 kW.