22.4 liters of ammonia were dissolved in 186 g of sulfuric acid, calculate the mass of the formed salt.

2NH3 + H2SO4 = (NH4) 2SO4
n (H2SO4) = m \ M = 186 \ 98 = 1.9 mol
n (NH3) = V \ Vm = 22.4 \ 22.4 = 1 mol
NH3 is in short supply, we calculate on it
n ((NH4) 2SO4) at ur-th p-i = 0.5 mol
m ((NH4) 2SO4) = nM = 0.5 * 132 = 66 g
Answer: 66 g



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