22.4 liters of carbon dioxide were dissolved in 100 g of 30% sodium hydroxide solution. Calculate the mass of the formed salt

The reaction between sodium hydroxide and carbon dioxide is described by the following chemical reaction equation:

2NaOH + CO2 = Na2CO3 + H2O;

With an excess of carbon dioxide, the following reaction occurs:

NaOH + CO2 = NaHCO3;

Two moles of alkali react with one mole of carbon dioxide.

Determine the amount of substance in 100 grams of a 30% solution of caustic and 22.4 liters of carbon dioxide.

M NaOH = 23 + 16 + 1 = 40 grams / mol;

N NaOH = 100 x 0.3 / 40 = 0.75 mol;

Under normal conditions, 1 mole of ideal gas takes up a volume of 22.4 liters.

N CO2 = 1 mol;

Since there is an excess of carbon dioxide, we get 0.75 mol of NaHCO3.

Let’s determine the mass of salt.

M NaHCO3 = 23 + 1 + 12 + 16 x 3 = 54 grams / mol

m NaHCO3 = 54 x 0.75 = 40.5 grams;