22.4 liters of carbon monoxide under normal conditions reacts with oxygen. Find the amount of carbon dioxide emitted?

Let’s implement the solution:
1. Let’s write the equation according to the problem statement:
V = 22.4 liters. X l. -?
2СО + О2 = 2СО2 – ОВР, carbon monoxide was obtained (4);
3. Calculations of molar masses:
M (CO) = 28 g / mol;
M (CO2) = 44 g / mol.
4. Determine the number of moles of the starting material:
1 mol of gas at normal level is 22.4 liters, which means that Y (CO) = 1 mol.
Y (CO2) = 1 mol since the amount of these substances according to the equation is 2 mol.
5.V (CO2) = 1 * 22.4 = 22.4 liters.
Answer: during the reaction, carbon dioxide is released in a volume of 22.4 liters.