22.4 sulfur oxide was passed through 100 g of a 5.6% potassium hydroxide solution 4.

22.4 sulfur oxide was passed through 100 g of a 5.6% potassium hydroxide solution 4. Determine the mass fraction of the formed salt in the solution

Let’s compose the reaction:

KOH + SO2 = KHSO3.

First of all, it is necessary to find the amount of KOH and SO2.

n (SO2) = m / M = 22.4 / 64 = 0.35 mol.

In order to find the amount of a substance KOH, it is necessary to find the mass of this substance. Therefore, we multiply the mass of the solution by the mass fraction.

m in. (KOH) = m p. * ω = 100 * 0.056 = 5.6 g;

n (KOH) = m / M = 5.6 / 56 = 0.1 mol;

n (KOH) = n (KHSO3) = 0.1 mol.

To determine the mass of KHSO3, the quantity must be multiplied by the molar mass.

m (KHSO3) = n * M = 0.1 * 120 = 12 g.

Answer: 12 g.