23 grams of sodium reacted with sulfuric acid, how many liters of gas did you get?

1. Let’s compose the equation for the reaction of sodium with sulfuric acid:

2Na + H2SO4 = Na2SO4 + H2 ↑;

2. Let’s calculate the chemical amount of sodium:

n (Na) = m (Na): M (Na) = 23: 23 = 1 mol;

3. Set the amount of released hydrogen:

n (H2) = n (Na): 2 = 1: 2 = 0.5 mol;

4. Let’s calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: 11.2 liters.