250 g of limestone containing 20% impurities was dissolved in acetic acid, and 33.6 liters of carbon dioxide

250 g of limestone containing 20% impurities was dissolved in acetic acid, and 33.6 liters of carbon dioxide were obtained. What is the volume fraction of carbon dioxide output? What is the volume fraction of the output of carbon dioxide from the theoretically possible.

When calcium carbonate reacts with acetic acid, calcium acetate, water and carbon dioxide gas are produced. The reaction is described by the following equation:

CaCO3 + 2CH3COOH = Ca (CH3COO) 2 + CO2 ↑ + H2O;

Let’s calculate the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 250 x 0.8 / 100 = 2 mol;

Dissolving this amount of limestone in acetic acid will produce the same amount of carbon dioxide.

Let’s calculate its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 2 x 22.4 = 44.8 liters;

We practically got 33.6 liters.

The reaction yield is:

K = 33.6 / 44.8 = 0.75 = 75%;



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