252 g of nitric acid reacted with excess sodium hydroxide. Calculate the mass of the salt
| March 4, 2021 | education
252 g of nitric acid reacted with excess sodium hydroxide. Calculate the mass of the salt obtained if the mass fraction of the salt yield is 90%.
The mass of nitric acid is 252 g.
Mass fraction of the output – 90%.
Determine the mass of the resulting salt.
We write down the reaction equation.
HNO3 + NaOH = NaNO3 + H2O.
Determine the molar mass of nitric acid and sodium nitrate.
M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol.
M (NaNO3) = 23 + 14 + 16 * 3 = 84 g / mol.
Next, you need to make up the proportion.
252 g of nitric acid – x g of salt.
63 g / mol – 84 g / mol.
X = 336 g.
Let’s define the mass mass.
336 * 0.9 = 302.4 g.
Answer: the mass of sodium nitrate is 302.43 g.
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