3.36 L of hydrogen sulfide was passed through the solution containing sodium hydroxide.

3.36 L of hydrogen sulfide was passed through the solution containing sodium hydroxide. Determine the mass (g) of the formed medium salt.

2NaOH + H2S = Na2S + 2H2O

n (H2S) = 3.36 / 22.4 = 0.15 mol;

According to the stoichiometry of the reaction:

n (Na2S) = n (H2S) = 0.15 mol;

m (Na2S) = n (Na2S) * M (Na2S) = 0.15 * 78 = 11.7 g.



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