3 acetylene with a volume of 10.08 l benzene was obtained, the mass fraction

3 acetylene with a volume of 10.08 l benzene was obtained, the mass fraction of the product yield is 70%, determine the mass of the benzene obtained

3 C2H2 (t, ° С, catalyst) —-> С6H6

The amount of acetylene: n (C2H2) = V / Vm = 10.8 L / 22.4 L = 0.48 (mol).

The amount of benzene: n (C6H6) = 0.48 mol / 3 = 0.16 (mol).

The theoretical mass of benzene: m (theoretical) = 0.16 * 78 = 12.48 (g).

Benzene yield: m (practical) / m (theoretical) = yield. Whence it follows that:

m (practical) = m (theoretical) * yield = 12.48 * 0.7 = 8.736 (g).