3 liters of water were poured into a cylindrical vessel with a bottom area of 100 cm2. how much pressure does water put on the bottom of the vessel
Initial data: S (area of the bottom of the vessel) = 100 cm ^ 2 = 0.01 m ^ 2; V (volume of water in the vessel) = 3 l = 3 * 10 ^ -3 m ^ 3.
Reference data: ρ (water density) = 1000 kg / m ^ 3; g (acceleration due to gravity) = 10 m / s ^ 2.
The pressure that water will exert on the bottom of a cylindrical vessel can be determined by the following formula:
P = Ft / S = m * g / S = ρ * V * g / S = 3 * 10 ^ -3 * 1000 * 10 / 0.01 = 3000 Pa = 3 kPa.
Answer: At the bottom of a cylindrical vessel, water exerts a pressure of 3 kPa.
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