30 g of calcium reacted with hydrochloric acid. Find the volume of the evolved gas and the mass of the salt obtained.

To solve the problem, write down the equation:
m = 30 g. X g. -? X L. -?
1. Ca + 2HCl = CaCl2 + H2 – OBP, obtained calcium chloride, hydrogen gas;
1 mol 1 mol 1 mol;
2. Calculations:
M (Ca) = 40 g / mol;
M (CaCl2) = 111 g / mol;
M (H2) = 2 g / mol.
3. Determine the number of moles of the starting material, if the mass is known:
Y (Ca) = m / M = 30/40 = 0.75 mol;
Y (CaCl2) = 0.75 mol;
Y (H2) = 0.75 mol since the amount of these substances according to the equation is equal to 1 mol.
4. Find the mass and volume of products:
m (CaCL2) = Y * M = 0.75 * 111 = 83.25 g;
V (H2) = 0.75 * 22.4 = 16.8 liters.
Answer: in the course of the reaction, calcium chloride with a mass of 83.25 g was obtained, hydrogen with a volume of 16.8 liters was released.