33.6 L of hydrogen reacted with copper oxide II. Determine the mass of copper and hydrogen

33.6 L of hydrogen reacted with copper oxide II. Determine the mass of copper and hydrogen as a result of the reaction.

The volume of hydrogen is 33.6 liters.

Let’s determine the mass of copper and hydrogen as a result of the reaction.

First, you need to write down the reaction equations.

H2 + CaO = Ca + H2O.

Let’s determine the amount of hydrogen substance.

n = V / Vm = 33.6 / 22.4 = 1.5 mol.

Let’s determine the mass of hydrogen.

m = n * M.

M (H2) = 2 * 1 = 2 g / mol.

m = 1.5 * 2 = 3 g.

The mass of hydrogen is 3 grams.

Let’s determine the amount of copper substance.

1.5 moles of hydrogen – x moles of copper.

1 mol – 1 mol.

X = 1.5 mol.

Let’s determine the mass of copper.

M (Ca) = 64 g / mol.

m = 1.5 * 64 = 96 g.

Answer: 96 g.