33.6 L of hydrogen sulphide was burned in excess of oxygen. Calculate the V of the resulting So2 if the yield is 90%.

The oxidation reaction of hydrogen sulfide with oxygen proceeds in accordance with the following chemical equation:

H2S + 3/2 O2 = H2O + SO2;

Let’s calculate the chemical amount of hydrogen sulfide. To do this, we divide its volume by the volume of 1 mole of gas (filling 22.4 liters).

N H2S = 33.6 / 22.4 = 1.5 mol;

Taking into account the reaction yield of 90%, the amount of sulfur dioxide will be 1.5 x 0.90 = 1.35 mol;

Let’s calculate the volume of sulfur dioxide. For this purpose, we multiply the molar amount of the substance by the volume of 1 mole of gas (which is 22.4 liters).

V SO2 = 1.35 x 22.4 = 30.24 liters;