35 grams of Mg containing 10% impurities reacted with sulfuric acid to determine the volume of hydrogen.
| August 12, 2021 | education
The mass of magnesium is 35 g.
The mass fraction of impurities is 10%.
Determine the volume of hydrogen reacted.
We write down the reaction equation.
Mg + H2SO4 = MgSO4 + H2.
Next, we determine the mass of pure magnesium. We write down the solution.
100 – 10 = 90%.
35 * 0.9 = 31.5 g.
Next, using the reaction equation, we determine the mass of hydrogen. For this, the molar mass of hydrogen and the molar mass of magnesium should be determined.
M (Mg) = 24 g / mol.
M (H2) = 1 * 2 = 2 g / mol.
31.5 g magnesium – x g hydrogen.
24 g / mol magnesium – 2 g / mol hydrogen
X = 2 * 31.5 / 24 = 2.625 g / mol.
Therefore, the mass of hydrogen is 2.625 g.
Answer: 2.625 g.
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