4.48 L of methane was pyrolyzed. Determine the volume of hydrogen and the mass of carbon obtained as a result of pyrolysis.

1. Let’s make the equation:
CH4 = 2H2 + C – methane pyrolysis occurs at a temperature of 1200 degrees, carbon and hydrogen are released;
M (CH4) = 16 g / mol;
M (H2) = 2 g / mol;
M (C) = 12 g / mol.
Determine the amount of moles of methane:
1 mol of gas at n, y – 22.4 liters.
X mol (CH4) -4.48 L. hence, X mol (CH4) = 1 * 4.48 / 22.4 = 0.2 mol.
Let’s make the proportion:
0.2 mol (CH4) – X mol (H2);
– 1 mol -2 mol from here, X mol (H2) = 0.2 * 2/1 = 0.4 mol.
Find the volume of hydrogen:
V (H2) = 0.4 * 22.4 = 8.96 liters.
The number of moles of methane and carbon according to the reaction equation are equal to 1 mol, which means that Y (C) = 0.2 mol.
Let’s calculate the mass of carbon by the formula:
m (C) = Y * M = 0.2 * 12 = 2.4 g.
Answer: the mass of carbon is 2.4 g, the volume of hydrogen is 8.96 liters.