460 g of sodium and chlorine reacted. Find the volume of chlorine.

1. To solve the problem, we compose the equation:
m = 460 g. X l. -?
2Na + Cl2 = 2NaCl – compounds, sodium chloride obtained;
2. Calculations:
M (Na) = 22.9 g / mol;
Y (Na) = m / M = 460 / 22.9 = 20 mol.
3. Proportion:
20 mol (Na) – X mol (Cl2);
– 2 mol – 1 mol from here, X mol (Cl2) = 1 * 20/2 = 10 mol.
4. Find the volume of Cl2:
V (Cl2) = 10 * 22.4 = 224 HP
Answer: 224 liters of chlorine is required to carry out the process.