5.68 grams of H3AsO4 reacted with NaOH solution. What is the mass of the reaction product?
| April 9, 2021 | education
When arsenic acid interacts with sodium hydroxide, a salt is formed – sodium hydrogen arsenate.
H3AsO4 + 2NaOH = Na2HAsO4 + 2H2O.
The number of moles of acid.
n (H3AsO4) = m / Mr = 5.68 g / 142 g / mol = 0.04 mol.
The number of moles of the formed salt and acid will be equal.
n (H3AsO4) = n (Na2HAsO4) = 0.04 mol.
The mass of the salt is.
m (Na2HAsO4) = n • Mr = 0.04 mol • 186 g / mol = 7.44 g.
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