5 g of magnesium oxide was treated with a solution containing 31.5 g. nitric acid.
| September 6, 2021 | education
5 g of magnesium oxide was treated with a solution containing 31.5 g. nitric acid. Calculate the mass of the salt formed.
Magnesium oxide mass – 5 g.
The mass of nitric acid is 31.5 g.
Determine the mass of the resulting salt.
We write down the reaction equation for this problem.
MgO + 2HNO3 = Mg (NO3) 2 + H2O.
Determine which substance is in excess. First, we determine the molar mass of magnesium oxide and nitric acid.
M (MgO) = 40 g / mol.
M (HNO3) = 15 + 48 = 63 g / mol.
X g of magnesium oxide – 31.5 g of nitric acid.
40 g / mol – 2 * 63 g / mol.
X = 10 g.
Therefore, we find the mass of salt for magnesium oxide.
5 g of magnesium oxide – in g of magnesium nitrate.
40 g / mol – 148 g / mol.
Y = 18.5 g.
Answer: 18.5 g.
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