5 kg of sand containing 10% impurities was fused with an excess of sodium hydroxide to obtain 9 kg of product. Calculate the sodium silicate yield as a percentage of the theoretically possible
Let’s write the reaction equation:
SiO2 + 2NaOH → Na2SiO3 + H2O (conditions: temperature; sodium silicate).
Let’s find the mass of silicon oxide (sand) without impurities:
m (SiO2) = (mtot. * w (SiO2)) / 100% = (5000 g * 90%) / 100% = 4500 g.
Let’s find the amount of silicon oxide substance:
n (SiO2) = m (SiO2) / M (SiO2) = 4500 g / 60 g / mol = 75 mol.
Let’s find the theoretical mass of sodium silicate:
n (Na2SiO3) = n (SiO2) = 75 mol.
m (Na2SiO3) = n (Na2SiO3) * M (Na2SiO3) = 75 mol * 122 g / mol = 9150 g = 9.15 kg.
Let’s calculate the yield of sodium silicate:
n (Na2SiO3) = (mpract. (Na2SiO3) * 100%) / mtheoret. (Na2SiO3) = (9 kg * 100%) / 9.15 kg = 98.36%.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.