5 minutes after the start of the movement, the motorcyclist developed a speed

5 minutes after the start of the movement, the motorcyclist developed a speed of 5 m / s. find the force imparting acceleration if the mass is 200 kg.

These tasks: t (time elapsed after the start of movement) = 5 min (in SI t = 300 s); V (the speed that the motorcyclist in question was able to develop) = 5 m / s; m (mass) = 200 kg.

The force that imparted the acceleration to the motorcyclist under consideration is determined by the formula: F = m * a = m * (V – V0) / t = m * (V – 0) / t = m * V / t.

Let’s calculate: F = 200 * 5/300 = 3.33 N.

Answer: Acceleration of the motorcyclist in question was reported by a force of 3.33 N.