50 grams of pure acid was added to a 40% solution, after which the concentration

50 grams of pure acid was added to a 40% solution, after which the concentration of the solution became 60%. Find the initial mass of the solution.

Condition:

Was – 40% -? gram

Added – 50 grams.

Became – 60%.

1) Find how many percent of the solution was added.

60 – 40 = 20%.

2) Now we will find 1% of the given solution.

50/20 = 2.5 grams.

3) Now we can find out how much the solution has become after adding.

2.5 * 60 = 150 grams – it became after adding.

4) And now it remains only from how much it was to subtract how much was added, and we will find out how much the solution was initially.

150 – 50 = 100 grams – it was originally.

Answer: 100 grams of the solution was originally.



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