560 g of potassium hydroxide reacts with sulfuric acid. What mass of salt will this make?

Given: m (KOH) = 560 g, potassium hydroxide reacts with sulfuric acid.

Find: m (K2SO4) -?

Solution:

Let’s write down the reaction equation.

KOH + H2SO4 = K2SO4 + H2O

Let’s arrange the coefficients:

2KOH + H2SO4 = K2SO4 + 2H2O

Let’s calculate the molar mass of potassium hydroxide and potassium sulfate.

M (KOH) = 56 g / mol

M (K2SO4) = 208 g / mol

Above KOH we write 560 g, and under – 112 g. Above K2SO4 – x g, and under – 208 g.

Let’s compose and solve the proportion:

x = 560 * 208/112 = 1040 g

Answer: 1040