6 * 10²¹ electrons pass through the cross-section of the contact wire in 2 s.

6 * 10²¹ electrons pass through the cross-section of the contact wire in 2 s. Determine the amperage. The electron charge is qe = 1.6 * 10 ^ -19 C.

t = 2 s.
N = 6 * 10 ^ 21.
qe = 1.6 * 10 ^ -19 Cl.
I -?
According to the definition: the current I is the charge Q, which passes through the cross-section of the conductor per unit of time t: I = Q / t.
Let us find the value of the charge Q, since N electrons have passed and the charge of each electron is qe, then Q = N * qe.
I = N * qe / t.
I = 6 * 10 ^ 21 * 1.6 * 10 ^ -19 C / 2 s = 480 A.
Answer: the current in the contact wire is I = 480 A.