6.5 zinc was placed in a solution containing 20 g of sulfuric acid. Calculate the mass of the salt formed during this.

Let’s write the reaction equation:

Zn + H2SO4 → ZnSO4 + H2 (zinc sulfate, hydrogen).

Let’s calculate the amount of zinc substance:

n (Zn) = m (Zn) / M (Zn) = 6.5 g / 65 g / mol = 0.1 mol.

Let’s calculate the amount of sulfuric acid substance:

n (H2SO4) = m (H2SO4) / M (H2SO4) = 20 g / 98 g / mol = 0.204 mol.

For 0.1 mol of zinc, 0.1 mol of sulfuric acid is required, which means the acid is in excess. We are calculating zinc.

Let’s calculate the amount of zinc sulfate substance:

n (ZnSO4) = n (Zn) = 0.1 mol.

Let’s find the mass of salt:

m (ZnSO4) = n (ZnSO4) * M (ZnSO4) = 0.1 mol * 161 g / mol = 16.1 g.

Answer: 16.1 grams.