6.72 L of ammonia was passed through the solution containing sulfuric acid until a medium

6.72 L of ammonia was passed through the solution containing sulfuric acid until a medium salt was formed. the mass of the formed salt is

Solution:
1. Let’s compose the reaction equation:
H2SO4 + 2NH3 = (NH4) 2SO4 – reaction of the compound, ammonium sulfate was obtained;
2. Let’s calculate the amount of moles of ammonia according to Avogadro’s law:
1 mol of gas occupies a volume of 22.4 liters (at n. At);
X mol (NH3) – 6.72 L. Hence, X mol (NH3) = 1 * 6.72 / 22.4 = 0.3 mol;
3. Let’s make the proportion according to the equation:
0.3 mol (NH3) – X mol (NH4) 2SO4;
-2 mol -1 mol hence, X mol (NH4) 2SO4 = 0.3 * 1/2 = 0.15 mol;
4. Calculate the mass of ammonium sulfate by the formula:
m (NH4) 2SO4 = Y * M = 0.15 * 132 = 19.8 g.
Answer: the mass of the ammonium sulfate salt is 19.8 g.