6.72 L of carbon dioxide was passed into the sodium hydroxide solution. Calculate the mass of sodium

6.72 L of carbon dioxide was passed into the sodium hydroxide solution. Calculate the mass of sodium carbonate formed.

1. Let’s write down the equation of chemical interaction:

2NaOH + CO2 = Na2CO3 + H2O.

2. Find the chemical number of the reacted carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = V (CO2) / Vm = 6.72 l / 22.4 l / mol = 0.3 mol.

3. Using the equation of chemical interaction, we find the chemical number and, as a result, the mass of the released sodium carbonate:

n (Na2CO3) = n (CO2) = 0.3 mol.

m (Na2CO3) = n (Na2CO3) * M (Na2CO3) = 0.3 mol * 106 g / mol = 31.8 g.

Answer: m (Na2CO3) = 31.8 g.