6 g of carbon burned out. Calculate: a) the volume of reacted oxygen; b) the volume of the formed carbon monoxide (IV)

C + O2 = CO2.
An equal number of moles of substances enter into the reaction:
n (C) = n (O2) = 1 mol.
The theoretical amount of substances that have reacted:
Mr (C) = 12 g / mol = m = 12 g.
V (O2) = 22.4 liters.
The practical value of burned carbon is 6 g, and oxygen is denoted by x:
6 g C – Chl O2.
12 g C – 22.4 L O2.
Find x:
V (O2) = 6 * 22.4 / 12 = 11.2 liters.
Knowing that the amount of moles of starting materials and reaction products are equal, the volume of the formed carbon will be equal to
V (CO2) = V (O2) = 11.2 liters.