6 g of hydrochloric acid was combined with aluminum. Calculate the mass of the salt formed.

Let’s write the reaction equation:

2Al + 6HCl → 2AlCl3 + 3H2 (aluminum chloride, hydrogen; substitution reaction).

1) Calculate the amount of hydrochloric acid substance:

n (HCl) = m (HCl) / M (HCl) = 6 g / 36.5 g / mol = 0.164 mol.

Since the mass of aluminum is not given, we can neglect it.

2) Let’s calculate the amount of aluminum chloride substance:

n (AlCl3) = 1/3 * n (HCl) = 1/3 * 0.164 mol = 0.055 mol.

3) Calculate the mass of the formed salt:

m (AlCl3) = n (AlCl3) * M (AlCl3) = 0.055 mol * 133.5 g / mol = 7.3425 g.

Answer: 7.3425 grams.