6 mol of phosphorus burned out, what amount of m (P2O5), m (O2), and v (O2).

To solve, we write down the equation:
1. 4P + 5O2 = 2P2O5 – combustion of phosphorus, phosphorus oxide is formed (5);
2. Calculations:
M (P) = 30.9 g / mol.
M (O2) = 32 g / mol.
M (P2O5) = 141.8 g / mol.
3. Proportions:
6 mol (P) – X mol (O2);
– 4 mol -5 mol from here, X mol (O2) = 6 * 5/4 = 7.5 mol (substance in excess).
Y (P) = 6 mol (deficient substance).
Calculations are made for the substance in deficiency.
6 mol (P) – X mol (P2O5);
– 4 mol – 2 mol from here, X mol (P2O5) = 6 * 2/4 = 3 mol.
4. Find the mass of the product:
m (P2O5) = Y * M = 3 * 141.8 = 42.54 g.
Answer: received phosphorus oxide weighing 42.54 g.