6 seconds after the start, the bus speed was 4.8m / s. How long after the start of the movement

6 seconds after the start, the bus speed was 4.8m / s. How long after the start of the movement will the bus speed become equal to 24m / s?

Initial data: V0 (initial speed of the bus) = 0 m / s; t1 (first time after the start of movement) = 6 s; V1 (bus speed after time t1) = 4.8 m / s; V2 (required bus speed) = 24 m / s.

The time elapsed after the start of the bus movement is determined by the formula: t2 = (V2 – V0) / a = V2 / (V1 / t1) = V2 * t1 / V1.

Calculation: t2 = 24 * 6 / 4.8 = 30 s.

Answer: The bus will reach a speed of 24 m / s 30 seconds after the start of movement.