6 × 10 ^ 21 electrons pass through the cross section of the contact wire in 2 s. Determine the amperage in the wire.

Initial data: t (duration of electron motion) = 2 s; N (the number of electrons passed through the contact wire) = 6 * 10 ^ 21 electrons.

Reference data: e (value of the electron charge) = 1.6 * 10 ^ -19 Cl.

1) Determine the charge that will pass through the contact wire: q = N * e = 6 * 10 ^ 21 * 1.6 * 10 ^ -19 = 960 Cl.

2) We calculate the current in the contact wire: I = q / t = 960/2 = 480 A.

Answer: The current in the contact wire is 480 A.