60 kilograms of water taken at 90 degrees. Mixed with 150 kilograms of water taken at a temperature of 23 degrees

60 kilograms of water taken at 90 degrees. Mixed with 150 kilograms of water taken at a temperature of 23 degrees, the final temperature of the resulting mixture is 40 degrees. How much heat was released into the environment during mixing.

Task data: m1 (hot water mass) = 60 kg; t1 (hot water temperature before mixing) = 90 ºС; m2 (mass of cool water) = 150 kg; t3 (cool water temperature) = 23 ºС; t (equilibrium temperature) = 40 ºС.

Constants: Cw (heat capacity of water) = 4200 J / (kg * K).

Heat loss during mixing: Q = Q1 – Q2 = Cw * m1 * (t1 – t) – Cw * m * (t – t2).

Calculation: Q = 4200 * 60 * (90 – 40) – 4200 * 150 * (40 – 23) = 1.89 * 106 J (1.89 MJ).

Answer: 1.89 MJ of heat was released into the environment.