600 ml of solution contains 11 g of calcium chloride. calculate the molar concentration of this solution

Given:
V solution (CaCl2) = 600 ml = 0.6 l

To find:
Cm (CaCl2) -?

Decision:
1) Mr (CaCl2) = Ar (Ca) + Ar (Cl) * 2 = 40 + 35.5 * 2 = 111 g / mol;
2) n (CaCl2) = m (CaCl2) / Mr (CaCl2) = 11/111 = 0.1 mol;
3) Cm (CaCl2) = n (CaCl2) / V solution (CaCl2) = 0.1 / 0.6 = 0.17 mol / l = 0.17 M.

Answer: The molar concentration of CaCl2 is 0.17 M.



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