620 grams of sodium orthophosphate, treated with the required amount of sulfuric acid.

620 grams of sodium orthophosphate, treated with the required amount of sulfuric acid. Calculate the mass of phosphoric acid formed if the acid yield is 90% of the theoretical

Let us write the equation for the reaction of obtaining phosphoric acid:

2Na3PO4 + 3H2SO4 = 3Na2SO4 + 2H3PO4

for each mole of Na orthophosphate (molar mass M = 164 g), 1 mol of acid (M = 98 g) is obtained.

Na3PO4 reacted 620/164 = 3.78 mol, which means that the acid turned out:

98 * 3.78 * 90% = 333.44 g