64.8 zinc oxide was reduced with excess carbon. Determine the mass of the formed metal

| February 3, 2021 | education

64.8 zinc oxide was reduced with excess carbon. Determine the mass of the formed metal if the reaction product yield is 65%

1. Let’s write the equation according to the problem statement:
m = 64.8 g. X g. -? W = 65%
ZnO + C = Zn + CO – ОВР, obtained zinc, carbon monoxide (2);
1 mol 1 mol.
2. Calculations by formulas:
M (ZnO) = 81.3 g / mol;
M (Zn) = 65.3 g / mol.
3. Determine the number of moles of the starting material, if the mass is known:
Y (ZnO) = m / M = 64.8 / 81.3 = 0.8 mol;
Y (Zn) = 0.8 mol since the amount of these substances according to the equation is 1 mol.
4. Find the theoretical mass of metal:
m (Zn) = Y * M = 0.8 * 65.3 = 52.24 g;
W = m (practical) / m (theoretical) * 100;
m (practical) = 0.65 * 52.24 = 33.95 g.
Answer: during the reduction process, zinc with a mass of 33.95 g was obtained.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.