67.2 ml of ammonia was dissolved in 730 mg of a 20% hydrochloric acid solution.

67.2 ml of ammonia was dissolved in 730 mg of a 20% hydrochloric acid solution. how many mg of ammonium chloride was formed in this case?

The reaction of ammonia with hydrogen chloride is described by the following chemical reaction equation:

NH3 + HCl = NH4Cl;

When one mole of ammonia reacts with one mole of hydrochloric acid, one mole of ammonium chloride is formed.

Let’s find the available quantities of the substance.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

The amount of substance in 67.5 ml of hydrochloric acid will be:

N NH3 = 67.5 / 1000 / 22.4 = 0.003 mol;

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 0.73 x 0.2 / 36.5 = 0.004 mol;

In the reaction of 0.003 mol of ammonia with 0.003 mol of hydrochloric acid, 0.003 mol of ammonium chloride is formed.

M NH4Cl = 53.5 grams / mol;

m NH4Cl = 0.003 x 53.5 = 0.161 grams = 161 mg;