7 liters of pure water were added to three liters of a 20% sulfuric acid solution. Determine the concentration of the new solution.
1) Determine the mass of sulfuric acid in a 20% solution if we know that the entire mass of this solution is 3 liters.
3 l = 3000 grams.
3000 – 100%
X – 20%;
X = 3000 * 20/100;
X = 600 grams.
2) We find out the mass of the new solution if we know that another 7 liters of pure water have been added to it.
3 + 7 = 10 liters.
10 l = 10000 grams.
3) Let us determine what concentration the new solution has become if we know that there are 600 grams of sulfuric acid in it.
10000 – 100%
600 – X%;
X = 600 * 100/10000;
X = 6%.
Answer: The new solution was 6% concentration.
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