7 liters of pure water were added to three liters of a 20% sulfuric acid solution.

7 liters of pure water were added to three liters of a 20% sulfuric acid solution. Determine the concentration of the new solution.

1) Determine the mass of sulfuric acid in a 20% solution if we know that the entire mass of this solution is 3 liters.

3 l = 3000 grams.

3000 – 100%

X – 20%;

X = 3000 * 20/100;

X = 600 grams.

2) We find out the mass of the new solution if we know that another 7 liters of pure water have been added to it.

3 + 7 = 10 liters.

10 l = 10000 grams.

3) Let us determine what concentration the new solution has become if we know that there are 600 grams of sulfuric acid in it.

10000 – 100%

600 – X%;

X = 600 * 100/10000;

X = 6%.

Answer: The new solution was 6% concentration.