730 grams of 1% hydrochloric acid solution was added to 26 grams of zinc shavings.
730 grams of 1% hydrochloric acid solution was added to 26 grams of zinc shavings. Question – dilute the mass of salt in the solution after the end of the reaction.
Zn + 2HCl = ZnCl2 + H2.
* We calculate the amount of hydrochloric acid substance:
1) The mass of the solute of hydrochloric acid in its solution: 1 * 730/100 = 7.3 g.
2) The molar mass of hydrochloric acid: 1 + 35.5 = 36.5.
3) Amount of hydrochloric acid substance: 7.3 / 36.5 = 0.2 mol.
* We calculate the amount of zinc substance:
65/26 = 2.5 mol.
* Lack of hydrochloric acid. The calculation is carried out on it.
* According to the reaction equation, there is one mole of zinc chloride for two moles of hydrochloric acid. The amount of chloride substance is: 0.2 * 2 = 0.4 mol.
* The mass of zinc chloride is: 136 * 0.4 = 54.4 g – the answer.