740 g of calcium hydroxide reacts with sulfuric acid. calculate the mass of the resulting salt.

Let’s write down the solution:
1. Let’s compose the equation:
1 mol 1 mol;
Ca (OH) 2 + H2SO4 = CaSO4 + 2H2O – ion exchange reaction, obtained calcium sulfate in the sediment;
2. Calculation of the molar masses of substances:
M Ca (OH) 2 = 74 g / mol;
M (CaSO4) = 136 g / mol.
3. Determine the number of moles of calcium hydroxide by the formula:
Y Ca (OH) 2 = m / M = 740/74 = 10 mol;
Y (CaSO4) = 10 mol since the amounts of these substances are equal to 1 mol.
4. Find the mass of CaSO4 salt:
m (CaSO4) = Y * M = 10 * 136 = 1360 g.
Answer: the mass of the reaction product of calcium sulfate is 1360 g.